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kodGreya [7K]
3 years ago
15

What does this symbol, 1/0N, mean?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
3 0

An element can be represented symbolically in terms of its atomic number and mass number as:

\[_{Z}^{A}\textrm{X}\]

where X = symbol of the element

A = atomic mass

Z = atomic number

In this case we have the representation as:

\[_{0}^{1}\textrm{n}\]

where n = symbol for neutron

mass number of neutron = 1

charge/atomic number of neutron = 0

Ans: D) A neutron of zero charge and one unit mass

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Answer:

B

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Answer:

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Explanation:

A. We know that the internal energy,ΔU = q + w where q = quantity of heat and w = work done on system.

1. In the above q = -7.9 J (the negative indicating heat loss by the system). w = 3.6 J (It is positive because work is done on the system). So, the internal energy for this system is ΔU₁ = q + w = -7.9J + 3.6J = -4.3 J

ii. From the question q = +1.5 J (the positive indicating heat into the system). w = -7.5 J (It is negative because work is done by the system). So, the internal energy for this system is ΔU₂ = q + w = +1.5J + (-7.5J) = +1.5J - 7.5J = - 6.0J

B. We know that ΔU = U₂ - U₁ where U₁ and U₂ are the initial and final internal energies of the system. Since for the systems above, the initial internal energies U₁ are the same, then we say U₁ = U. Let U₁ and U₂ now represent the final energies of both systems in A i and A ii above. So, we write ΔU₁ = U₁ - U and ΔU₂ = U₂ - U where ΔU₁ and ΔU₂ are the internal energy changes in A i and A ii respectively. Now from ΔU₁ = U₁ - U, U₁ = ΔU₁ + U and U₂ = ΔU₂ + U. Subtracting both equations U₁ - U₂ = ΔU₁ - ΔU₂

= -4.3J -(-6.0 J)= 1.7 J. Since U₁ - U₂ > 0 , U₂ < U₁ , so the second system's internal energy increase less and is lower in energy and is more stable.

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