Answer:
first option
Step-by-step explanation:
Given 2 secants to a circle from an external point, then
The product of the external part and the whole of one secant is equal to the external part and the whole of the other secant, that is
PQ(RP) = PS(TP)
Answer: answer is b on edg
Step-by-step explanation:
Answer:
x²+y²-4x-6y+12.75=0
Step-by-step explanation:
The equation is given by (x-h)²+(y-k)²=r²
center is (2,3), so h=2, k=3,r=0.5
equation is given by;
(x-2)²+(y-3)²=0.5²
Expand
x(x-2)-2(x-2)+y(y-3)-3(y-3)=0.5²
4-2x-2x+x²+9-3y-3y+y²=0.25
4-4x+x²+9-6y+y²=0.25
x²-4x+13+y²-6y=0.25
x²-4x+y²-6y+13=0.25
x²-4x+y²-6y+12.75=0
x²+y²-4x-6y+12.75=0
my answer here would either be A) or C)
