All categories

3 years ago

What is the highest common factor of 36 and 56???

Mathematics

2 answers:

Orlov [11]3 years ago

5 0

Answer:

The highest common factor of 36 and 56 is number6

irakobra [83]3 years ago

5 0

Answer:

Step-by-step explanation:

Greatest common factor (GCF) of 36 and 56 is 4.

Step-1: Prime Factorization of 36

Prime factors of 36 are 2, 3. Prime factorization of 36 in exponential form is:

36 = 2^2 × 3^2

Step-2: Prime Factorization of 56

Prime factors of 56 are 2, 7. Prime factorization of 56 in exponential form is:

56 = 2^3 × 7^1

Step-3: Factors of 36

List of positive integer factors of 36 that divides 36 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18

Step-4: Factors of 56

List of positive integer factors of 56 that divides 36 without a remainder.

1, 2, 4, 7, 8, 14, 28

Final Step: Biggest Common Factor Number

We found the factors and prime factorization of 36 and 56. The biggest common factor number is the GCF number.

So the greatest common factor 36 and 56 is 4.

You might be interested in

A real estate agent wants to know how many owners of homes worth over $1,000,000 might be considering putting their home on the

JulsSmile [24]

Answer:

Step-by-step explanation:

The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:

N: The number of observations in the population.
n: The number of observations in the sample.
The way that the random sample is chosen.

We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is

μ_x=p

σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]

In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:

σ_x = σ / sqrt(n).

6 0

3 years ago

Seven years ago, kodi found a box of old baseball cards in the garage. since then, he has added a consistent number of cards to

Katena32 [7]

(3,52)(7,108)
slope = (108 - 52) / (7 - 3) = 56/4 = 14

y = mx + b
slope(m) = 14
(3,52)...x = 3 and y = 52
sub and find b, the y int (the original amount of cards)
52 = 3(14) + b
52 = 42 + b
52 - 42 = b
10 = b

so ur equation is y = 14x + 10....with x being the number of years and y being the total cards. <== ur equation is y = 14x + 10

He started with 10 cards....and has been adding 14 cards every year.

so after 10 years...
y = 14(10) + 10
y = 140 + 10
y = 150 <== after 10 years, he will have 150 cards

8 0

3 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

3 years ago

Read 2 more answers

If 4x + 8x + 12x + 16x is equal to 5 + 10 + 30 + 40 then what is the value of x

zloy xaker [14]

4x+8x+12x+16x=5+10+30+40

4x+8x+12x+16x= 85

40x=85

x= 85/40

x=2.125

7 0

3 years ago