Question

Help me please Only no.2 no.3 no.8 no.6 no.9 and no.10

Answer 1

Answer:

2) x³ (x² + 1) (x + 1)

3) (x - 6) (x + 6)

6)  (x + 3) (x - 4)

8) (5x + 3) (x - 2)

Step-by-step explanation:

I'm providing the solutions for numbers 2, 3, 6, and 8, in order to give you the opportunity to apply and practice the techniques demonstrated here for numbers 9 and 10.

2) x⁶ + x⁵ + x⁴ + x³ = 0

Factor out the highest possible common term, applying the product rule of exponents, $a^{m} a^{n} = a^{m+n}$

x³ (x³ + x² + x¹ + 1) = 0

Next, apply the special factoring technique into the exponential expressions inside the parenthesis), the factor by grouping:

The factors for the given polynomial are: x³ (x² + 1) (x + 1)

3) x² - 36 = 0

Use the difference of two squares factoring, where it states: u² - v² = (u - v) (u + v)

Since 36 is a perfect square of 6², then we can establish the following factors using the difference of squares:

Factors:  (x - 6) (x + 6).

6) x² - x - 12 = 0

For this quadratic trinomial, find factors that will produce a product of a × c (1 × -12) and sum of b (-1):

The possible factors of -12 that also results to a sum of -1 are:  

3 × -4 = -1

 Hence, the possible factors of x² - x - 12 = 0 could be (x + 3) (x - 4). Verify whether this is correct by performing the FOIL method:

(x + 3) (x - 4) = x² - 4x + 3x - 12 = x² - x - 12

Therefore, the factors of x² - x - 12 = 0 are: (x + 3) (x - 4).

8) 5x² - 7x - 6 = 0

where a = 5, b = -7, and c = -6

Given this quadratic trinomial, we can use the factoring by grouping, where it states: find the values of u and v such that the product of uv is the same as the product of ac:  u × v = a × c, and that the sum of (u + v ) is the same as b.  

In other words, we must find the factors of u × v that have a product of a × c and a sum of b:

u × v = a × c = 5 × (-6) = -30  

u + v = b = -7

The possible factors of -30 are:

-3 × 10 = -30

3 × -10 = -30

Out of these factors, the factors 3 × -10 = -30 will have the same sum as the value of b = -7:

3 + (-10) = -7

Hence, u = 3, v = -10.

Now, we can group the trinomial as follows:

(ax² + ux ) + (vx + c )

(5x² + 3x) + (-10x - 6)

For the last step, factor out the common terms from both groups:

(5x² + 3x) + (-10x - 6)  

x (5x + 3) - 2(5x + 3)

Combine common terms together: (5x + 3) and (x - 2)

Therefore, the factors of the given quadratic trinomial are: (5x + 3) (x - 2).