All categories

2 years ago

Help please!!

Mathematics

1 answer:

stepladder [879]2 years ago

4 0

Answer:

it changed 21 Fahrenheit

Step-by-step explanation:

-14.8 - 6.2 = -21

and minus + minus = +

so, -14.8 + 21 = 6.2

i think so that is the right answer

You might be interested in

the slide at the playground has a height of 6 feet.The base of the slide measured on the ground is 8 feet.what is the length of

NemiM [27]

The formula for finding the length is
${a}^{2} + {b}^{2} = {c}^{2}$
All we have to do is plug in the numbers.

${6}^{2} + {8}^{2} = {c}^{2}$
36 + 64 = 100

Since 100 =
${c}^{2}$
we have to find the square root.

$\sqrt{100} = 10$

The length of the slide is 10 feet.

6 0

2 years ago

Tom is trying to write 2 3/47 as a decimal

exis [7]

It's about 2.064 if you make the number an improper fraction then divide

5 0

2 years ago

Giving Brainlies!! 14. How many tests did the student take during their junior year in high school? (1 point)

inessss [21]

Hi there.

The answer is definitely "D" because on the graph it shows there are only 29 students that did the test.

8 0

3 years ago

Read 2 more answers

If f(x)=x+11 and g(x)=3x^2, find (f+g)(x) and (f+g)(5).

Stella [2.4K]

(f+g)(x) = f(x) + g(x) = x + 11 + 3x^2
(f+g)(5) = f(5) + g(5) = 5 + 11 +3(5^2) = 91

8 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

---

Learn more about Algebra I: brainly.com/question/27698547

---

Topic: Algebra I

6 0

1 year ago