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mafiozo [28]
3 years ago
14

ass="latex-formula">
Mathematics
2 answers:
suter [353]3 years ago
7 0
Answer:

X - 12 = 14
+12. +12

X = 26
Leya [2.2K]3 years ago
3 0

Answer:

x=26

Step-by-step explanation:

  • x-12=14
  • x=14+12
  • x=26

<em><u>Mark </u></em><em><u>as </u></em><em><u>brainliest</u></em><em><u> if</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>. </u></em>

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At a team meeting, 80% of the tennis team was there. If there were 12
Illusion [34]

Answer:

15 people

Step-by-step explanation:

let x=total # of people on the team

80%=12

80/100=12/x

cross multiply

80x=1200

division property of equality (divide both sides by 80)

x=15

There are 15 people on the team.

8 0
3 years ago
F the equation of a circle is (x + 4)2 + (y - 6)2 = 25, its radius is 5
BartSMP [9]
Yes the radius is 5.  Is this a true or false question or is there something you forgot to add to it?
3 0
4 years ago
Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)
Likurg_2 [28]

Answer:

d = 14

(-2,-1)

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-9-5)^2+(-1-(-1))^2}
  2. Simplify:                        d = \sqrt{(-9-5)^2+(-1+1)^2}
  3. Subtract/Add:               d = \sqrt{(-14)^2+(0)^2}
  4. Evaluate:                       d = \sqrt{196}
  5. Evaluate:                       d = \14

<u>Step 3: Find Midpoint</u>

  1. Substitute:                    (\frac{5-9}{2},\frac{-1-1}{2})
  2. Subtract:                       (\frac{-4}{2},\frac{-2}{2})
  3. Divide:                          (-2,-1)
7 0
3 years ago
Which of the following represents the ratio of the hypotenuse to the given side?
mixas84 [53]

Answer:c

Step-by-step explanation:

hyp=6\sqrt{2}

adj=6

hyp:adj=6\sqrt{2}  :2

hyp:adj=\frac{6\sqrt{2} }{6} \\

=\frac{\sqrt{2} }{1} \\hyp:adj=\sqrt{2} :1

3 0
4 years ago
Which sequence of transformations proves that shape I is similar to shape II?
4vir4ik [10]
Note that if you simply reflected it and dilated it, it would be too far to the left

note that the distances bewteen the axises in image 1 were 1 and 3in image 3,the distances are 2 and 6
seems to be 3 times
so it's the 90 counterclockwise rotation and dilation by scale factor of 3
answer is last one

4 0
4 years ago
Read 2 more answers
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