The coordinates would be (3, 3).
The slope from R to S is given by
m = (0 - 0)/(-4-1) = 0/-5 = 0
The distance from R to S is 5 units straight across.
This means the slope from T to U will be 0, and it will be a horizontal segment. This means the y-coordinate of U will be 3, since the y-coordinate of T is 3.
The distance from T to U will be 5 as well; -2+5 = 3 for the x-coordinate.
This makes the point (3, 3).
Technically, none of the equations.
The equation you're looking for would be:
x²+(x+20)²=150²
1. y<span> ≤ 4x/3+5
2. y</span><span>< 6x/4+3</span>
Answer:
108
Step-by-step explanation:
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
First substitute x into the expression
= 9²-81/√9 - 3
= 81-81/3-3
= 0/0 (indeterminate)
Apply l'hospital rule
= lim x -> 9 d/dx(x²-81)/√x - 3
= lim x -> 9 2x/1/2√x
Substitute x = 9
= 2(9)/1/2√9
=18/1/(2(3)
=18 × 6/1
= 108
Hence the limit of the function is 108
