The answer to the question they gave you is D
2b) stretching
2c) it is stretched by a factor of 2 of the parent function f(x)=x
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Using the point on the graph (4, 1) solve for a
1 = a(4-3)² - 1
2 = a
(((1/y - 1) + (5/12)) = (-2/3y - 3))
((((1)(12)/12(y - 1) + (5(y + 1)/12(y + 1) = (-2/3y - 3))
((12/12y - 12) + (5y + 5/12y - 12)) = (-2/3y - 3))
((5y + 17/12y - 12) = (-2/3y - 3)
(12y - 12/5 + 17) × (5y + 17/12y - 12) = (-2/3y - 3)(12y - 2/5 + 17)
y = -21y + 4/66y - 66
y = -7/22 - 2/33
y = -25/66
The |*| symbols take away the negative value of a number. So |-3| is just “3”. I can explain more if needed :)
