Answer:
Step-by-step explanation:
i don't see the thing you put it just shows the question
Options are not shown but…
A square has 4 equal length sides and a right angle
Or two equal length diagonals which are perpendicular
Or 4 right angled corners and two adjacent sides equal
Or perpendicular diagonals with the same midpoint
Using the last one…
Gradient of AC = (5 - 3)/(-3 - 3) = 2/-6 = -1/3
Gradient of BD = (7 - 1)/(1 - -1) = 6/2 = 3
-1/3 x 3 = -1 so AC and BD are perpendicular
Midpoint of AC = ((-3 + 3)/2 , (5 + 3)/2) = (0, 4)
Midpoint of BD = ((1 + -1)/2 , (7 + 1)/2) = (0, 4)
QED
Answer:
big
Step-by-step explanation:
2
Answer:
see explanation
Step-by-step explanation:
given a parabola in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex which is also the axis of symmetry is
= -
y = 3x² - 24x + 38 is in standard form
with a = 3, b = - 24 and c = 38, hence
= - = 4
Substitute x = 4 into the equation for corresponding y- coordinate
y = 3(4)² - 24(4) + 38 = 48 - 96 + 38 = - 10
vertex = (4, - 10)
equation of axis of symmetry is x = 4