Answer:
![y=-\frac{5}{3} x-\frac{42}{5}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B3%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
Step-by-step explanation:
Given the slope and another point, simply plug them into the point-slope formula to find your y-intercept.
![y-y1=m(x-x1)\\y-(-6)=\frac{3}{5} (x-4)\\y+6=\frac{3}{5} x-\frac{12}{5} \\y=\frac{3}{5} x-\frac{42}{5}](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29%5C%5Cy-%28-6%29%3D%5Cfrac%7B3%7D%7B5%7D%20%28x-4%29%5C%5Cy%2B6%3D%5Cfrac%7B3%7D%7B5%7D%20x-%5Cfrac%7B12%7D%7B5%7D%20%5C%5Cy%3D%5Cfrac%7B3%7D%7B5%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
Now that we've found your y-intercept, we have the original equation. To find the perpendicular equation, you need the opposite reciprocal of your slope.
To find the 'opposite,' change your slope's sign. Since your slope is positive
, the opposite is
.
To find the 'reciprocal,' flip your fraction. This will make your slope
.
Your final equation is:
![y=-\frac{5}{3} x-\frac{42}{5}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B3%7D%20x-%5Cfrac%7B42%7D%7B5%7D)
is the same thing here as the other triangles, the triangle below is an equilateral, the one above is an isosceles.
the <u>vertex</u> of the isosceles is 40°, so the twins angle at the <u>base</u> are (180 - 40)/2 = 70° = x each.
since the sides in the equilateral are all the same length, then 2y + 10 = x - y, but we already know what "x" is, so
![\bf 2y+10=x-y\implies 2y+10=\stackrel{x}{70}-y\implies 3y=60 \\\\\\ y=\cfrac{60}{3}\implies y=20](https://tex.z-dn.net/?f=%5Cbf%202y%2B10%3Dx-y%5Cimplies%202y%2B10%3D%5Cstackrel%7Bx%7D%7B70%7D-y%5Cimplies%203y%3D60%20%5C%5C%5C%5C%5C%5C%20y%3D%5Ccfrac%7B60%7D%7B3%7D%5Cimplies%20y%3D20)
Answer:
ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).
(0,−2)
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(−∞,∞)
Set-Builder Notation: {x|x ∈ R}
For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.
x y
−2 −4
−1 −3
0 −2
1 −3
2 −4
Step-by-step explanation:
I believe this is the correct answer Y= 3/2x+2
Hope this helped you and have a fantastic day!