Answer:
hey there guys ^^
Step-by-step explanation:
Answer:
oytqlrvlh<u>q</u><u>x</u><u>t</u><u>q</u><u>l</u><u>x</u><u>p</u><u>l</u><u>y</u><u>m</u><u>p</u><u>x</u><u>m</u><u>h</u><u>m</u><u>r</u>
Must be
(c) 12.11.10
Or
(d) 12
.23 and .24 is your answer.
<h2>Greetings!</h2>
Answer:
One number is
and the other number is ![\frac{1}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B7%7D)
Step-by-step explanation:
Let x be the smaller number and y be the bigger number.
x = x
y = 5x
6x + 3y = 3
6x + (3 * 5x) = 3
6x + 15x = 3
(÷3)
2x + 5x = 1
7x = 1
x = ![\frac{1}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B7%7D)
6x + 3y = 3
6(
) + 3y = 3
+ 3y = 3
3y = 3 - ![\frac{6}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B7%7D)
3y = ![\frac{15}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B7%7D)
Divide both sides by 3 to get 1y:
y = ![\frac{5}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B7%7D)
So one number is
and the other number is ![\frac{1}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B7%7D)
<h2>Hope this helps!</h2>