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shtirl [24]
3 years ago
14

Find the sum. (- 7/2 z + 4) + (1/5 z - 15) HELPPP

Mathematics
1 answer:
Nonamiya [84]3 years ago
8 0

Answer:

-33/10z - 11

Step-by-step explanation:

since all of these terms are being added, there are no need for the parenthesis

-7/2z +4 + 1/5z -15

add like terms (to add the fractions, convert them to a common denominator)

-7/2z + 4 + 1/5z - 15

-35/10z + 2/10z - 11

-33/10z - 11

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Is -12.161616 rational
Mars2501 [29]

Answer:

depends

Step-by-step explanation:

If you mean just -12.161616, then it’s rational.

If you mean recurring decimal, then it’s not.

8 0
3 years ago
Paula's grades on her history tests this semester are: 79,93, 92, 86, and
Vinvika [58]

Answer:

4.4

Step-by-step explanation:

Data set = 79, 93, 92, 86, 90

Xmean = (79 + 93 + 92 + 86 + 90)/5

= 440/5

Xmean = 88

MAD =

(79 - 88) + (93 - 88) + ( 92 - 88) + ( 86 - 88) + ( 90 - 88)/ 5

=

(9) + (5) + (4) + (2) + (2)/ 5

=

22/5

Mean Absolute Deviation = 4.4

5 0
4 years ago
Read 2 more answers
A store has apples on sale at $3.00 for 2 pounds.
sergeinik [125]
5 ounces × 24 apples= 120 ounces of apples

1 pound= 16 ounces

120 ounces = 7.5 pounds

$3 = 2 pounds

$11.25 = 7.5 pounds.

You cannot but 24 apples for $9 because each apple is five ounces, so you multiply each apple by its weight, and get 120 ounces. Since there is 16 ounces in 1 pound, you have 7.5 pounds of apples. If 2 pounds is three dollars then 7.5 can't be nine.
4 0
3 years ago
A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
DaniilM [7]
<span>A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
The area of the circle will be found as follows:
the fraction of the sector=15/360=1/24
the area of the circle will be:
area=(fraction of the circle)/(fraction of the sector)*(area of the sector)
=1/(1/24)</span>×11.9
=285.6 m²
5 0
3 years ago
What is the value of log(x exponent 2 y exponent 3 divided by z) when given the following:
Gekata [30.6K]

Answer:

B. 13

Explanation:

\sf\:Given\:expression: log(\dfrac{x^2 y^3}{z} )

Logarithm rules:

\sf (i)  \ \sf log(ab) = log(a) + log(b)\\ \\ (ii) \  log(a/b) = log(a) - log(b)\\\\ (iii) \ log(a^n) = n log(a)

Breakdown of the expression:

\rightarrow \sf log\left(\dfrac{x^2y^3}{z}\right)

\rightarrow \sf log\left(x^2\right) + log\left(y^3\right) - log(z)

\rightarrow \sf 2\log\left(x\right)+3\log \left(y\right)-\log \left(z\right)

insert given values

\rightarrow \sf 2(3)+3(2)-(-1)

\rightarrow \sf 13

7 0
2 years ago
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