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3 years ago

12

A few seconds ago i posted a really hard question, but this one is WAY more hard, whats 2 + 4? (i doubt that anyones brain is bi

g enough, but if it is, ill give brainliest!)

1 answer:

Gelneren [198K]3 years ago

7 0

Answer:

Dude why did you do this to us it's too hard

Step-by-step explanation:

P.S. It' 6

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Please help (puppy eyes)

-Dominant- [34]

First we have to find the decimal equivalent by dividing.
5 / 8 = 0.625

It can't be an Integer because decimals can't be intergers, so that's ruled out

It can't be repeating as it does end, so that's also ruled out

Since the decimal does end it can't be non-terminating, non-repeating

So the answer is Terminating Decimal by process of elimination

7 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation 5c=250

Elis [28]

Answer:

c = $log_{5}$ 250

Step-by-step explanation:

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3 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

Lilit [14]

Check the picture below.

$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$

7 0

3 years ago

Read 2 more answers

What goes into 49 and 50 evenly

solniwko [45]

Nothing, goes into 49 and 50.

8 0

3 years ago

Read 2 more answers

Problem 7.1 (10 points) Let pXnqn"0,1,... be a Markov chain with state space S " t1, 2, 3u and transition probability matrix P "

12345 [234]

Answer:

The responses to the given can be defined as follows:

Step-by-step explanation:

For point a:

fixing probability vector that is $W = [a b c]$

$\therefore$

relation: $WT =W$

$\to 0.5a+0.3b+0.2c=a ..................(1)\\\\ \to 0.4a+0.4b+0.3c=b..............(2)\\\\ \to 0.1a+0.3b+0.5c=c.................(3)$

solving the value:

$a=0.3387 \\\\ b=0.3710\\\\ c=0.2903$

Therefore the stationary distribution $\pi =[0.3387 \ 0.3710\ 0.2903]$

For point b:

$\pi$ will be limiting distribution if $\pi_j=\lin_{n\to \infity} (X_n=\frac{j}{X_0}=i) \Sigma_{\sqrt{j}} n_j=1$

$\pi$ satisfies the above condition so, it is limiting the distribution.

3 0

2 years ago