The situation will be represented by linear equation, this is given by:
y=ax+b
where:
a=slope=rate
b=y-intercept
from our situation:
a=-1/20
b=5 ft
thus the equation modeling the situation will be:
y=-1/20x+5
Answer: y=-1/20x+5
Answer:
Yes.
If they do, their intersection is a line.
= 12x + 15y because 3 x 4x = 12x and 3 x 5y = 15y
This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
