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Grace [21]
3 years ago
11

A network administrator is planning redundant devices and cabling in a switched network to support high availability. Which bene

fit will implementing the Spanning Tree Protocol provide to this design?
Computers and Technology
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

Redundant paths can be available without causing logical Layer 2 loops.

Explanation:

  • Spanning Tree Protocol is used to allow redundancy in the Layer 2 switched networks without creating cycles/circles also called loops.
  • These loops are called physical loops.
  • When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
  • This affects the performance of the network as the result of broadcast packets flooding.
  • STP puts one port of the switch to forward mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to block mode and the one port that is left after this is placed in forward mode.
  • Spanning Tree Algorithm is used by STP to determine the optimal path  of switch to the network.
  • Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
  • This information helps STP to eliminate the redundant paths.
  • So this is how STP tracks all the links in the switched network and eliminates redundant loops by allowing only one active path to the destination while blocking all other paths.
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Answer:

import random

computer = random.randint(0, 2)

user = int(input("scissor (0), rock (1), paper (2): "))

if computer == 0:

   if user == 0:

       print("The computer is scissor. You are scissor too. It is a draw")

   elif user == 1:

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   elif user == 2:

       print("The computer is scissor. You are paper. Computer won")

elif computer == 1:

   if user == 0:

       print("The computer is rock. You are scissor. Computer won")

   elif user == 1:

       print("The computer is rock. You are rock too. It is a draw")

   elif user == 2:

       print("The computer is rock. You are paper. You won")

elif computer == 2:

   if user == 0:

       print("The computer is paper. You are scissor. You won")

   elif user == 1:

       print("The computer is paper. You are rock. Computer won")

   elif user == 2:

       print("The computer is paper. You are paper too. It is a draw")

Explanation:

*The code is in Python.

Import the random to be able to generate number number

Generate a random number between 0 and 2 (inclusive) using randint() method and set it to the computer variable

Ask the user to enter a number and set it to the user variable

Check the value of computer the computer variable:

If it is 0, check the value of user variable. If user is 0, it is a draw. If user is 1, user wins. If user is 2, computer wins

If it is 1, check the value of user variable. If user is 0, computer wins. If user is 1, it is a draw. If user is 2, user wins

If it is 2, check the value of user variable. If user is 0, user wins. If user is 1, computer wins. If user is 2, it is a draw

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