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3 years ago

8

the equation of a circle is x - y + 1 = 0 . if one end of the diameter is ( 3, p) and other end is ( a, 2 ) , find the equation

of the circle.

1 answer:

erma4kov [3.2K]3 years ago

8 0

I gave the answer earlier, but here is the solution again, along with a graph proving it is correct.

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MULTIPLE CHOICE

Dvinal [7]

Step 1) Multiply 2 by 3

<em>5x+6 = 2x+3x+6</em>

Step 2) Combine like terms

<em>5x+6 = 5x+6</em>

Step 3) Add 5x and 6 to both sides

Answer:

<em>0 = 0</em>

4 0

3 years ago

The table shows the maximum and minimum depths of two submarines. Find the range of depths for each submarine. Then determine wh

JulsSmile [24]

Answer:

Range A = 386ft

Range B = 427ft

B has the larger range.

Explanation:

To find the range, find the difference between the minimum and maximum depths for each submarine. Remember that your answer will be positive.

Sub A:

-146ft - (-532ft) = 386 ft

Sub B:

-194ft - (-621ft) = 427 ft

Submarine B has a larger range.

7 0

3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

3 years ago

Suppose it is known that for a given differentiable function y=f(x), its tangent line (local linearization) at the point where a

AleksandrR [38]

Answer:

y(-4) = 5

y'(-4) = -7

Step-by-step explanation:

Hi!

Since the tangent line T and the curve y must coincide at x=-4

y(-4) = T(-4) = 5

On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7

That is:

y'(-4) = -7

6 0

2 years ago

solve the following word problem. use x for the unknown value. the average cost of a car in 2013 is said to be 5 less than twice

Rashid [163]

Let the average cost of car in 2009 be $x, then the average cost of a car in 2013 is 2x - 5
25,000 = 2x - 5
2x = 25,000 + 5 = 25,005
x = 25,005/2 = $12,502.50

7 0

3 years ago