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erik [133]
3 years ago
9

HELP ME PLEEEAAASSSEEEEE​

Mathematics
1 answer:
Ronch [10]3 years ago
4 0

J. (6, 5)

<em>Hope</em><em> </em><em>that</em><em> </em><em>helped</em><em>:</em><em>)</em>

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I need help, please! ASAP.
dmitriy555 [2]

Answer:

Formula for percent change is C = {x_2 - x_1}/{x_1}  

C = relative change

x_1 = initial value

x_2 = final value

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the derivative of a power function using the power rule
taurus [48]
Let’s make up a random function, say:

f(x) = x^6

Now by power laws we can break this up into two parts:
f(x) = (x^2)*(x^4)

Since we are now multiplying two functions we can apply the product rule:

f’(x) = (2x)(x^4) + (x^2)(4x^3)

Now we can simplify since we are only dealing with x’s:

f’(x) = 2x^5 + 4x^5
f’(x) = 6x^5

If we do the power rule of our initial function, you will find that the two are equal.

Hope this helps!!
5 0
3 years ago
The next model of a sports car will cost 5.6% less than the current model. The current model costs $52,000. How much will the pr
Lostsunrise [7]

Answer:

49,088

Step-by-step explanation:

First you need to find 5.6% of 52,000. Simply multiply 52,000 by 0.056 (change the percent to a decimal) then you get 2,912.

Second, you need to subtract 2,912 from 52,000 which is 49,088

8 0
3 years ago
Please help Will mark brainliest Algebra
Anestetic [448]
It's D I think? I might be wrong, but it cant be A or B because if you plug in 0 as x it doesnt give you the y-intercept of 3 for either. I would wait for another answer just in case though :)
8 0
4 years ago
A researcher surveys middle-school students on their study habits. She finds that in a random sample of 28 middle-school student
Readme [11.4K]

Answer:

The margin of error is  E = 1.96 *  \frac{ 0.92}{\sqrt{28 } }

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  28

     The  sample  mean is  \= x  =  2.4 \ hr

      The  standard deviation is  \sigma =  0.92  \ hr

     

Given that the confidence level is 95% the the level of significance can be evaluated as

             \alpha  =  100 -95

            \alpha  =  5 \%

             \alpha  = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table,the value is  Z_{\frac{\alpha }{2} } =  Z_{\frac{0.05}{2} } =  1.96

Generally the margin of error is mathematically represented as

           E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

          E = 1.96 *  \frac{ 0.92}{\sqrt{28 } }

         E = 0.3408

5 0
4 years ago
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