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ohaa [14]
2 years ago
11

What is the solution to the following equation?

Mathematics
2 answers:
allsm [11]2 years ago
6 0

Answer:

c 5

Step-by-step explanation:

mote1985 [20]2 years ago
3 0
The answer is C, x = 5
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A certain type of bacteria doubles in population every hour. Their growth can be modeled by an exponential equation. Initially,
Nastasia [14]
    <span> A: y=2x 15 (or whatever variables you choose to represent the colony growth and time)

B: y=2(3.5) 15;
22 colonies

C: substitute 584 with y into the original equation, so:
584=2x 15
569=2x
284.5=x; therefore, after 284.5 hours</span> Hope this helps! :D
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%3D%200" id="TexFormula1" title=" {x}^{2} + 2x = 0" alt=
Alex

Answer:

\textbf{Hello!}

\Longrightarrow2^2+2z=0

\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}

\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}

\Longrightarrow =\sqrt{2^2-0}

\Longrightarrow =\sqrt{2^2}

\Longrightarrow=2

\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}

\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}

\Longrightarrow\frac{-2+2}{2\cdot \:1}

\Longrightarrow =\frac{0}{2\cdot \:1}

\Longrightarrow =\frac{0}{2}

=0

\Longrightarrow\frac{-2-2}{2\cdot \:1}

\Longrightarrow =\frac{-4}{2\cdot \:1}

\Longrightarrow =\frac{-4}{2}

\Longrightarrow =-\frac{4}{2}

=-2

x=0,\:x=-2\Longleftarrow

\underline{HOPE ~IT~HELPS}

5 0
3 years ago
Emiko needs to go to the dentist. It takes her 65 minutes to get there on her bike. This is 5 minutes shorter then twice the tim
kakasveta [241]

Answer:

30 minutes by bus

Step-by-step explanation:

Equation: b = bus

b = (65 - 5) / 2

b = 60/2

b = 30 mins

Please give Brainliest :)

6 0
3 years ago
Mr. Lopez wrote the equation 32g+8g-10g=150
Brrunno [24]

Answer: g=5

Step-by-step explanation: combine like terms then divide.

8 0
3 years ago
Read 2 more answers
h(x) = x ^ 2 - 7x - 8 1) What are the zeros of the function? Write the smaller first, and the larger second smaller I largerx =
kramer

Answer:

The zeros are x = -1 and x = 8

The vertex is (3.5, -20.25)

Step-by-step explanation:

When we have a quadratic equation like:

y = a*x^2 + b*x + c

The zeros of the function are the values of x such that:

a*x^2 + b*x + c = 0

And the solutions are given by the Bhaskara's equation, which is:

x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}

And the vertex is at:

x = -b/2a

The y-value at the vertex is the function evaluated in that point.

In this case, we have the equation:

h(x) = x^2 - 7*x - 8

Then:

a = 1

b = -7

c= -8

Replacing these in the Bhaskara's equation we get:

x = \frac{-(-7)  \pm \sqrt{(-7)^2-4*1*(-8)} }{2*1} = \frac{7   \pm 9 }{2}

Then the two solutions are:

x = (7 - 9)/2 = -2/2 = -1   (this is the smaller one)

and

x = (7 + 9)/2 = 16/2 = 8  (this is the larger one)

And we will have the vertex at:

x = -(-7)/2*1 = 7/2 = 3.5

Evaluating h(x) in 3.5 we get:

h(3.5) = (3.5)^2 - 7*(3.5) - 8 = -20.25

Then the vertex is the point:

(3.5, -20.25)

5 0
3 years ago
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