Given m||n, find the value of x.<br><br> (2x-26)<br><br> (7X+8)

A tube feeding formula contains 6 grams of protein per each 80 ml of the formula. If the patient needs 120 grams of protein per

Anit [1.1K]

Answer:

1600 ml.

Step-by-step explanation:

Let x represent amount of tube-feeding formula.

We have been given that a tube feeding formula contains 6 grams of protein per each 80 ml of the formula.

To solve our given problem, we will use proportions as:

$\frac{x}{\text{120 gram}}=\frac{\text{80 ml}}{\text{ 6 grams}}$

$\frac{x}{\text{120 gram}}*\text{120 gram}=\frac{\text{80 ml}}{\text{ 6 grams}}*\text{120 gram}$

$x=\text{80 ml}*20$

$x=\text{1600 ml}$

Therefore, the patient should get 1600 ml of tube feeding formula every day.

3 0

2 years ago

Yesterday, 64% of the 6th grade students chose to drink chocolate milk with their lunch. What fraction of 6th grade students Did

Talja [164]

Answer:

$\frac{9}{25}$

Step-by-step explanation:

First subtract 100 and 64. To find how many didn't choose to drink chocolate milk.

100-64=36

Percentages put into fractions will be Percentage over 100.

So, the fraction will be $\frac{36}{100}$ . Now simplify.

$\frac{36}{100}=\frac{18}{50} =\frac{9}{25}$

4 0

3 years ago

Read 2 more answers

Dylan's hiking club is planning to stay overnight at a camping lodge. Each large room can hold 15 hikers. There are 168 hikers.

sukhopar [10]

Answer:

you would need 12 rooms

Step-by-step explanation:

168/12=11.2 so you would have 11 full rooms and then a room for the leftover two

4 0

2 years ago

Read 2 more answers

Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.

Alex17521 [72]

-2x + 6y = -34
-x + 3y = -17
x = 3y +17

Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)

Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)

7 0

2 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

2 years ago

Given m||n, find the value of x. (2x-26) (7X+8)