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Arturiano [62]
3 years ago
13

Carlos has 24 class play tickets. He sold 3/4 of the tickets.How many tickets did Carlos sell?

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
5 0
He sold 18 tickets. What you do is 4/1 time 3/4 and you'll get 18.
OverLord2011 [107]3 years ago
3 0
He sold 18 tickets class play tickets.  Hope this helps :) 



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Oliga [24]

QUESTION 9

The given right angle triangle has its two legs equal to x\:cm and the hypotenuse is 2\:units.


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x^2+x^2=2^2


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QUESTION 10


The given right angle triangle has its two legs equal to x\:units and the hypotenuse is 7\:units.


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x^2+x^2=7^2


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2x^2=7^2


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QUESTION 11

Sam divided the square backyard into two sections along the 40ft diagonal.

Let one of the sides of the garden be x\:units, then the other side of the garden is also  x\:units since it was a square backyard.


The diagonal is the hypotenuse which is 40ft and the two legs are  x\:units each.


Applying the Pythagoras Theorem, we have;

x^2+x^2=40^2


2x^2=1600


x^2=800


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The length of one side of the garden is approximately 28cm.


QUESTION 12

The hypotenuse of Nicole's right triangular support is 92cm long.


It was given that the two lengths of the triangular support are of equal length.


Let the two lengths of the triangular support be l\:cm each.


We then apply the Pythagoras theorem to obtain;

l^2+l^2=92^2


\Rightarrow 2l^2=8464


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\Rightarrow l=\sqrt{4232}


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Therefore Nicole needs l+l=65.05cm+65.05cm\approx130cm of wood to complete the support.

The correct answer is A.


QUESTION 13

A 45-45-90 triangle is an isosceles right triangle.


Let the length of the two legs be m\:inches each.

It was given that the hypotenuse of this triangle is 12\:inches.


Applying the Pythagoras Theorem, we have;

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QUESTION 15.

The distance from third base to  first base is also 127 ft to the nearest foot.


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3 years ago
Please help with this
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Answer:

D) x=\frac{-2+-2\sqrt{7} }{3}

Step-by-step explanation:

The quadratic formula is : \frac{-b+-\sqrt{b^2-4ac} }{2a}

A in terms of this question=9

B in terms of the question is 12

C in terms of the question is -24.

This question is an example of a quadratic equation. To work this out you may first need a calculator. The first step is to substitute the values of a,b and c into the formula.  So once substituted the formula of \frac{-b+-\sqrt{b^2-4ac} }{2a} becomes \frac{(-12)+-\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}. Although when written in a calculator there will not be a plus and minus button and so you would have to do this separately.

However when substituting the values it would be best practice to put them in brackets.

1) Substitute the values into the equation for +.

\frac{(-12)+\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /1.097167541

2) Substitute the values into the equation for -.

\frac{(-12)-\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /-2.430500874

8 0
3 years ago
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