3) Determne the largest multiple of 9 less than 200

In 1995, the moose population in a park was measured to be 1800. By 1998, the population was measured again to be 2400. If the p

Shalnov [3]

The linear equation for the variation of population is p = 200t + 1800.

<h3>What is an equation?</h3>

An equation is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

The formula for an equation in intercept form will be given as below:-

y = mx + c.

It is given that In 1995, the moose population in a park was measured to be 1800. By 1998, the population was measured again to be 2400.

Write the linear equation for population variation.

p = mt + c

m = Rate of change = ( 2400 - 1800 ) / 3 = 200, put the value in the equation.

p = 200t + c

Put the values in the equation to get the value of the constant.

2400 = 200 x 3 + c

c = 2400 - 600

c =1800

The equation for the linear variation of the population is,

p = 200t + 1800

Therefore, the linear equation for the variation of the population is p = 200t + 1800.

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6 0

2 years ago

Select the three number bonds that represent factor pairs of the num Number bond: 1 times 56 = 56. Number bond: 4 times 14 = 56.

MaRussiya [10]

Answer:

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

Step-by-step explanation:

As given,

Number bond: 1 times 56 = 56. .......(1)

Number bond: 4 times 14 = 56. .......(2)

Number bond: 5 times 6 = 56. .......(3)

Number bond: 7 times 8 = 56. .......(4)

Equation (1) represents factor pair of the number because

1 times 56 = 1× 56 = 56

It satisfies

Equation (2) represents factor pair of the number because

4 times 14 = 4× 14 = 56

It satisfies

Equation (3) does not represents factor pair of the number because

5 times 6 = 5× 6 = 30

It does not satisfies

Equation (4) represents factor pair of the number because

7 times 8 = 7× 8 = 56

It satisfies

So, the correct answer is -Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

8 0

3 years ago

Fracions closer to 1 than 0

ruslelena [56]

1 1/3, 1 1/4, 1 1/5 .....

Please vote my answer brainliest. thanks!

5 0

3 years ago

Read 2 more answers

**Spam answers will not be tolerated**

Morgarella [4.7K]

Answer:

$f'(x)=-\frac{2}{x^\frac{3}{2}}$

Step-by-step explanation:

So we have the function:

$f(x)=\frac{4}{\sqrt x}$

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

$\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Therefore, our derivative would be:

$\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}$

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

$=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}$

Place the 4 in front:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}$

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})$

Distribute:

$=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}$

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

$=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }$

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

$= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}$

The numerator will use the difference of two squares. Thus:

$=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Simplify the numerator:

$=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Both the numerator and denominator have a h. Cancel them:

$=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Now, substitute 0 for h. So:

$=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})$

Simplify:

$=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})$

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

$=4( \frac{-1}{(x)(2\sqrt{x})})$

Multiply across:

$= \frac{-4}{(2x\sqrt{x})}$

Reduce. Change √x to x^(1/2). So:

$=-\frac{2}{x(x^{\frac{1}{2}})}$

Add the exponents:

$=-\frac{2}{x^\frac{3}{2}}$

And we're done!

$f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}$

5 0

3 years ago

A hospital cafeteria has 20

Virty [35]

Answer:

Step-by-step explanation:

So if their is 65% of 20 tables with 6 chairs that's 13 tables.

And if their is 35% of 20 tables with 4 chairs that's 7 tables.

6 0

3 years ago

Read 2 more answers

3) Determne the largest multiple of 9 less than 200 ​

3) Determne the largest multiple of 9 less than 200