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Arte-miy333 [17]
2 years ago
14

Helpp need this done ASAP

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
7 0
Number two is proportional just do Y over X y/x meaning divided all the y’s over the x’s so 25 divided by 5 30 divided by 6 35/7 40/8 they all equal 5 so it’s proportional
number three isn’t proportional when you do y/x they all come out differently so you do y2-y1 over x2-x1 16-4/4-2 16-4=12 4-2=2 then you divided 12/2 that equals 6 you do that again but with the next numbers but they don’t equal so it’s no equation no constant
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PLEASE HELP ASAP!!
Art [367]

Answer:

See explanation

Step-by-step explanation:

A.  P(top)=top outcomes/all kinds of outcomes=4/30=2/15=13.33333333333...%

P(bottom)=bottom outcomes/ all kinds of outcomes=1/30=3.33333333....%

P(side)=25/30=5/6=83.33333333333...%

B. No. If were equally likely, the probabilities for A would have been roughly the same. It seems like the side event is more probable.

7 0
3 years ago
HELPP!!
Brilliant_brown [7]

Answer:

Hope this will help you.

5 0
3 years ago
What is the slope of the line represented by the equation y+3=4(x-5)?
Rudiy27

Answer:

the slope  is 4

Step-by-step explanation:

y+3=4(x-5)

This is in point slope form

y-y1=m(x-x1)

where (x1,y1) is a point on the line and m is the slope

The slope is 4 and a point on the line is (5,-3)

7 0
3 years ago
PLEASE ANSWER ILL GIVE CROWN TO RIGHT ANSWERR
nikdorinn [45]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
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