Let $f(x) = x^{10}+5x^9-8x^8+7x^7-x^6-12x^5+4x^4-8x^3+12x^2-5x-5$.
1 answer:
Plug in 1 and −1 to get two values of r(x) which is linear. From there you can get what a,b are in ax+b. Since f(x)=g(x)(x+1)(x−1)+r(x) we have f(1)=g(1)(1+1)(1−1)+r(1)=r(1)=−10 f(−1)=g(1)(−1+1)(−1−1)+r(−1)=r(−1)=16 We know the remainder is of degree 1 , so r(x)=ax+b and now we know, r(1)=ax+b=a+b=−10 r(−1)=ax+b=−a+b=16 so, solve a+b=−10 −a+b=16 which yields, a=−13 b=3 , so r(x)=−13x+3
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
= (4x+3)(−2x+−5)
= (4x)(−2x) + (4x)(−5) + (3)(−2x) + (3)(−5)
= −8x^2 − 20x − 6x − 15
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Answer:
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