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slega [8]
3 years ago
13

Balance equations practice

Chemistry
1 answer:
Margarita [4]3 years ago
3 0

Answer:

1 - B)    2 - B)     3 - A)

Explanation:

1. C3H8 + 5O2 → 3CO2 + xH2O.. Find 'X'.    

A) 3

B) 4

C) 5

D) 6

2. 4Al + 3O2 → xAl2O3. Find 'X'

A) 3

B) 2

C) 4

D) 5

3.  FeCl3 + 3NaOH → Fe(OH)3 + xNACl. Find 'x'

A)3

B) 4

C)5

D)6

More in Next Question...

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What is the amount of heat required to raise the temperature of 200.0 g of aluminum by 10°C? (specific heatof aluminum = 0.21 ca
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Answer:

We need 420 cal of heat

Explanation:

Step 1: Data given

Mass of the aluminium = 200.0 grams

Temperature rises with 10.0 °C

Specific heat of aluminium = 0.21 cal/g°C

Step 2: Calculate the amount of heat required

Q =m * c* ΔT

⇒with Q =  the amount of heat required= TO BE DETERMINED

⇒with m = the mass of aluminium = 200.0 grams

⇒with c = the specific heat of aluminium = 0.21 cal/g°C

⇒with ΔT = the change of temperature = 10.0°C

Q = 200.0 grams * 0.21 cal/g°C * 10.0 °C

Q = 420 cal

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A sample of 25 L of NH³ gas at 10°C is heated at constant pressure until it fills a volume of 50 L. What is the new temperature
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