All categories

3 years ago

Pls give a detailed explanation about what are enzyme mutations

Chemistry

1 answer:

OverLord2011 [107]3 years ago

3 0

Answer:

Enzyme mutations can lead to serious or fatal human disorders and are the consequence of inherited abnormalities in the affected individual's DNA. The mutation may be at a specific position in an enzyme encoded by a mutated gene, just like a single abnormal amino acid residue.

Explanation:

You might be interested in

Which of the following lists the stages of mitosis in order

AnnyKZ [126]

Anaphase

Metaphase

Prophase

Telophase

Interphase

Prometaphase

Explanation:

4 0

3 years ago

Read 2 more answers

An 80.0g sample of an unknown metal is at an initial temperature of 55.5oC. Afer 540 J of energy is absorbed by the metal, the t

Lunna [17]

Answer:

Specific heat of metal = 0.26 j/g.°C

Explanation:

Given data:

Mass of sample = 80.0 g

Initial temperature = 55.5 °C

Final temperature = 81.75 °C

Amount of heat absorbed = 540 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 81.75 °C - 55.5 °C

ΔT = 26.25 °C

540 j = 80 g × c × 26.25 °C

540 j = 2100 g.°C× c

540 j / 2100 g.°C = c

c = 0.26 j/g.°C

7 0

3 years ago

Ted likes to run long distances. He can run 20 km 20 km20, start text, space, k, m, end text in 95 9595 minutes. He wants to kno

balu736 [363]

Answer:

The distance in kilometer that Ted will go if he runs at the same pace for 285 minutes is 60km

Step-by-step explanation:

It was given that Ted Ted runs 20 km in 95 minutes, so for us to know how many kilometers he runs at the same pace for 285 minutes by using proportion.

For Ted to run 20 km in 95 minutes.

$Speed=Distance/Time$

where given distance= 20km

Given time =95minutes

Speed=20/95 .............eqn(1)

To calculate the distance in kilometers Ted will go if he runs at the same pace for 285 minutes, then

Speed= K/225 ...............eqn(2)

Let us represent distance with 'K'

Given time 225minutes

Equating eqn(1) and eqn(2)

Hence the proportion model that Ted could use in modelling this situation is this;

$20/95=K/225$

Cross multiply

K×95=20×225

$K=60$

The distance in kilometer that Ted will go if

he runs at the same pace for 285 minutes is 60km

3 0

3 years ago

Identify the parts of the energy diagram

Aliun [14]

On the first graph the beginning flat line is the reaction. Then comes the hill will it be call the activation energy. The final flat line would be the produce. Same names apply to the 2 graph too

7 0

3 years ago

Read 2 more answers

A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3

e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2 x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

n ( 5 x 12 + 8 x 1 + 4 x 16 ) = 132

n x ( 60 + 8 + 64 ) = 132

n = 1

Molecular formula = C₅H₈O₄.

3 0

3 years ago