Answer:
107.87 grams
Explanation:
One mole of silver weighs 107.87 grams
.
Answer:
Please find the complete question in the attached file.
Explanation:
Answer:
A) 2.76 x 103 kJ
Explanation:
CH3OH (I)--------->CO (g) + 2H2 (g)
Number of moles contained in 87.1g of hydrogen gas= mass of hydrogen gas/ molar mass of hydrogen gas
Molar mass of hydrogen gas= 2gmol-1
Number of moles hydrogen gas = 87.1g/2gmol-1= 43.55 moles of hydrogen
1 mole of methanol yields 2 moles of hydrogen
x moles of methanol yields 43.55 moles of hydrogen
x= 43.55 moles of hydrogen × 1 mole of methanol/2 moles of hydrogen
x= 21.775 moles of methanol
Then;
If 1 mole of methanol absorbs 128KJ of energy
21.775 moles of methanol will absorb 21.775 × 128/1 = 2.7×10^3 KJ of heat
The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
Learn more about stoichiometry:
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