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2 years ago

13

How much would it cost for the cans of paint that I need if I have a total area of 65.76 square feet, and each can that covers 2

0 square feet costs $4.98?

1 answer:

Masteriza [31]2 years ago

6 0

tienes que agregar y cuando agregas obtendrás 158 no me pongas como lista de ideas ok

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Tracy is finding the equation of a median-median line. She found that the equation of the line through the first and third summa

rodikova [14]

<span>1) Find the equation of the line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the line parallel to the previous line that passes through (x2, y2).
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted average of the
y-intercepts. b=(b1+b2+b1)/3 = (38+59+38)/3
b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>

7 0

3 years ago

I dont get this please help

Viktor [21]

Step-by-step explanation:

the side lengths of the base (the ground triangle) are equal. that means every ground side length is 8 in.

and that also makes the 3 triangles of the side areas of the pyramid equal.

so, for the surface area of the pyramid we need to calculate the area of one side area triangle, multiply it by 3 (as we have 3 side areas) and add the area of the ground triangle.

the area of a triangle is

baseline × height / 2

so, for a side area triangle we get

8 × 14 / 2 = 8×7 = 56 in²

all 3 side areas together are then

3×56 = 168 in²

the ground area triangle is then

8 × 6.9 / 2 = 4 × 6.9 = 27.6 in²

so, the total surface area of the pyramid is

168 + 27.6 = 195.6 in²

4 0

2 years ago

When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?

JulsSmile [24]

$3\cdot3^2-2\cdot5-(2\cdot3^2-3\cdot5)=27-10-(18-15)=17-3=14$

7 0

3 years ago

A gardener uses a coordinate grid to design a new garden. The gardener uses polygon WXYZ on the grid to represent the garden. Th

ValentinkaMS [17]

Answer:

A square

36 square yard.

Step-by-step explanation:

Given the following information:

W(3,3), X(-3,3), Y(-3,-3), and Z(3,-3)

So we need to graph those vertices and connect them in order.

(please have a look at the attached photo)

From the graph, it clear that the shape of the garden is a square.

Then, we need to calculate the length of the four sides

<u>Find the length of the side YZ. </u>

The length of side YZ = 3 + 3 = 6 yards because point Y and Z are on the same line y = -3 so we just need to find the distance between their x coordinate

<u>Find the length of the side WZ.</u>

The length of side WZ = 3 + 3 = 6 yards because point W and Z are on the same line x = 3 so we just need to find the distance between their y coordinate

=> the area of the square WXYZ:

= YZ*WZ

= 6*6

= 36 square yard.

7 0

3 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago