Answer:
the common difference is plus 3
Given:
m∠APD = (7x + 1)°
m∠DPC = 90°
m∠CPB = (9x - 7)°
To find:
The measure of arc ACD.
Solution:
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠APD + m∠DPC + m∠CPB = 180°
7x° + 1° + 90° + 9x° - 7° = 180°
16x° + 84° = 180°
Subtract 84° from both sides.
16x° + 84° - 84° = 180° - 84°
16x° = 96°
Divide by 16° on both sides.
x = 6
m∠APB = 180°
m∠BPD = (9x - 7)° + 90°
= (9(6) - 7)° + 90°
= 47° + 90°
m∠BPD = 137°
m∠APD = m∠APB + m∠BPD
= 180° + 137°
= 317°
<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>
m(ar ACD) = m∠APD
m(ar ACD) = 317°
The arc measure of ACD is 317°.
Answer:
3/2
Step-by-step explanation:
(3/4)/(1/2)=(3/4)(2/1)=6/4=3/2
Mine is protected view but it could be considered reading view although it might be editing view depending
Answer: 7 x + 6 = 6 x minus 3
Step-by-step explanation:
- 2 (x + 3) + 5 x = 3 (2 x minus 1)
- Now you distribute.
- 2(x) + 2(3) = 2x+6
- And 3(2x) minus 3(1) = 6x minus 3
- 2x+6+5x = 6x minus 3
- Then combine like terms
- 2x +5x=7x and there are no other like terms on either side of the equation.
- 7x+6= 6x minus 3