100 Joules have been used to roll the object up the ramp, but only 90 Joules were actually needed to lift the object, this means that 10 Joules have been wasted in the form of heat due to the friction between the object and the ramp, and this corresponds to
so, 10 % of the energy.
Answer:
-600 J
Explanation:
F₁ = 8i +29 j + 32k
F₂ = 48 i - 59 j - 22 k
F = F₁ +F₂ = 8i +29 j + 32k +48 i - 59 j - 22 k
F = 56i - 30 j + 10 k
displacement d = ( 0 - 20 )i + ( 0 - 15 )j + ( 7 -0) k
d = - 20 i - 15 j + 7 k
Work Done = F dot product d
F . d = - 56 x 20 - 30 x - 15 + 10 x 7
= - 1120 +450 + 70
= -600 J
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The correct option would be B. volts
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Answer:
the answer is A. A school crossing guard raises a stop sign that weigh 10 N
Answer:
Y = 3.39 x 10⁶ m
Explanation:
We will use Young's Double Slit formula here:
where,
Y = Fringe spacing = ?
λ = wavelength = 
= 8 x 10⁵ m
L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m
d = slit separation = 950 nm = 9.5 x 10⁻⁷ m
Therefore,
<u>Y = 3.39 x 10⁶ m</u>
