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NISA [10]
3 years ago
6

Find the ratio of average speed of a scooter moving at 30m/min and a car moving at 27km/hr

Physics
1 answer:
Pie3 years ago
7 0

30 m/min = 0.5 m/s (divide 30 by 60 s)

27 km/hr = 7.5 m/s (divide 27 by 3.6)

And then do the rest

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Elis [28]

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Primer can help seal the surface to protect against moisture and allow the paint to properly stick. Cover the area with primer, allowing the surface to dry according to the manufacturer's directions

Explanation:

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3 years ago
Scientists might make a computer model of volcanic eruptions. What is the
Anna [14]

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7 0
1 year ago
At a certain distance from the center of the Earth, a 0.4-kg object has a weight of 2.0 N. (a) Find this distance. (b) If the ob
Alika [10]

Answer:

a) The distance of the object from the center of the Earth is 8.92x10⁶ m.

b) The initial acceleration of the object is 5 m/s².

Explanation:

a) The distance can be found using the equation of gravitational force:

F = \frac{GMm}{r^{2}}

Where:

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

M: is the Earth's mass =  5.97x10²⁴ kg  

m: is the object's mass = 0.4 kg

F: is the force or the weight = 2.0 N    

r: is the distance =?

The distance is:

r = \sqrt{\frac{GMm}{F}} = \sqrt{\frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.97 \cdot 10^{24} kg*0.4 kg}{2.0 N}} = 8.92 \cdot 10^{6} m      

Hence, the distance of the object from the center of the Earth is 8.92x10⁶ m.

         

b) The initial acceleration of the object can be calculated knowing the weight:              

W = ma                                                  

Where:            

W: is the weight = 2 N

a: is the initial acceleration =?          

a = \frac{W}{m} = \frac{2 N}{0.4 kg} = 5 m/s^{2}

Therefore, the initial acceleration of the object is 5 m/s².

           

I hope it helps you!    

4 0
3 years ago
An old manuscript reveals that a landowner in the time of King Arthur held 3.00 acres of plowed land plus a livestock area of 25
iragen [17]

Answer:

(a) Total area is 14.5 roods

(b) Total area is 14674.522 square meters

Explanation:

Area occupied by land = 3 acres

1 acre = 40 perches by 4 perches = 160 square perches

3 acres = 3×160 = 480 square perches

Area occupied by livestock = 25 perches by 4 perches = 100 square perches

Total area = 480 + 100 = 580 square perches

1 rood = 4 perches by 1 perch = 4 square perches

580 square perches = 580/4 = 14.5 roods

(b) Total area = 580 square perches

1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters

580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters

8 0
3 years ago
For a wave, what term is defined as the maximum height of a crest, or depth of a trough, relative to the normal level? for a wav
sammy [17]
The appropriate response is amplitude. Amplitude is the target estimation of the level of progress (positive or negative) in environmental weight (the pressure and rarefaction of air atoms) created by sound waves.

I hope the answer will help you. 
6 0
3 years ago
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