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Arturiano [62]
4 years ago
11

Dentists' chairs are examples of hydraulic-lift systems. If a chair weighs 1400 N and rests on a piston with a cross-sectional a

rea of 1220 cm2, what force must be applied to the smaller piston with a cross-sectional area of 72 cm2 to lift the chair?
Physics
1 answer:
NeX [460]4 years ago
8 0

Answer:

Force applied to smaller cross section is

= 82.63 N

Explanation:

As we know

F_2 A_1 = F_1 A_2

where F1, F2 signifies the weight of the two chair in a hydraulic-lift system

And A_1, A_2 signifies the area of the two respective chairs in a hydraulic-lift system

Given -

F2=1400 N

A1 =1220 Square centimeter

A_2 = 72 Square centimeter

Substituting the given values in above equation, we get -

1400 * 72 = F1 * 1220\\F2 = 82.63

Force applied to smaller cross section is

= 82.63 N

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