All categories

2 years ago

Which equation represents a linear function that has a slope of 5 and a y-interceptof-6?

Mathematics

1 answer:

Alexus [3.1K]2 years ago

6 0

Answer:

y=5x-6

Step-by-step explanation:

Comparing y=5x-6 with y=mx+c,the slope is 5 and y intercept is-6

You might be interested in

Graph x^3-x^2-2x=0 what are the solutions of the equation

Aleks [24]

X^3 - x^2 - 2x = 0
x ( x^2 - x - 2 ) = 0
x (x-2) (x+1) = 0
x = 0
x-2 = 0 --> x = 2
x+1 = 0 --> x = -1

x = 0, x = 2, x = -1

7 0

2 years ago

7x-3y=-6 convert to slope intercept form

r-ruslan [8.4K]

I think 7x-y=-2 is the answer

3 0

3 years ago

.<br> Simplify the expression.<br><br> (7 – c)(–1)

Ganezh [65]

For this, you use the Law of Distribution and multiply -1 by all terms in the parentheses. 7 • -1 = -7; -c • -1 = c. Then you combine them, but since c is a variable, -7 + c is the most simplified it can get. I hope this helped!

7 0

3 years ago

A rectangular prism has a volume of 711.68 cubic inches. Long and 12.8 inches wide. What is the height of the prism?

oksian1 [2.3K]

Are the length and the width the same?

7 0

2 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago