Question

Dentermine whether this system of equations has one solution, no solution, or infinitely many solutions.

Answer 1

Answer: it has one solution

Step-by-step explanation:

Given :

$y = 8x + 2$ ................ equation 1

$y = -8x + 2$ ................. equation 2

Equating the two equation , we have

$8x + 2 = -8x + 2$

collecting the like terms

$8x + 8x = 2 - 2$

$16x = 0$

$x = 0$

substitute $x = 0$ into equation 1

$y = 8x + 2$

$y = 8(0) + 2$

$y = 2$

Therefore : it has one solution

Answer 2

It would be no solutions because

8x+2=-8x+2
+8x. +8x

16x +2 = 2
-2. -2

16x = 0

No solution