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Either a note page or some handouts
Brainiest?
Answer:
Part a: The program will print 3.
Part b: The program will print 4
Part c: The program will print 1.
Explanation:
Part a: As the scoping is static, the x integer has a value of 1 and the y integer has a value of 2 so the addition is 2+1=3.
Part b: As the scoping is dynamic with deep binding, the x integer has a value of 2 and the y integer has a value of 2 so the addition is 2+2=4.
Part c: As the scoping is dynamic with shallow binding, the x integer has a value of 1 so it will print 1.