Question

HELPPPP PLEASE WILLLL GIVE BRIANLIESTTTT

Answer 1

Answer: 105 mL

Explanation:

We can use the formula M₁V₁ = M₂V₂ the total volume of water that will yield 0.800 M HCl. We can then subtract that from the initial volume to get how much water needs to be added.

Since M₁V₁ = M₂V₂    (starting mole× starting volume = end mole × end volume)

⇒  (5 mol)(20 mL) = (0.80 mol) V₂

         100 mol/mL = 0.8 mol × V₂

⇒                      V₂ = 100 mol/mL ÷ 0.8 mol

                             = 125 m

Since we began with 20.0 mL of water,

water needed to add = 125 mL - 20 mL = 105 mL