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svet-max [94.6K]
3 years ago
11

HELPPPP PLEASE WILLLL GIVE BRIANLIESTTTT

Chemistry
1 answer:
aliina [53]3 years ago
6 0
<h2>Answer: 105 mL</h2>

<h3>Explanation:</h3>

We can use the formula M₁V₁ = M₂V₂ the total volume of water that will yield 0.800 M HCl. We can then subtract that from the initial volume to get how much water needs to be added.

Since M₁V₁ = M₂V₂    (starting mole× starting volume = end mole × end volume)

⇒  (5 mol)(20 mL) = (0.80 mol) V₂

         100 mol/mL = 0.8 mol × V₂

⇒                      V₂ = 100 mol/mL ÷ 0.8 mol

                             = 125 m

Since we began with 20.0 mL of water,

water needed to add = 125 mL - 20 mL = 105 mL

                                   

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