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Kruka [31]
3 years ago
12

How to convert chlorophenylamine to bromochlorobenzene

Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Answer:

hey buddy,This's your answer...!!

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Question:<br> What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?
STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

M=\frac{1.29mol}{0.350L}\\\\M=3.69M

Which gives molar units, M, or just mol/L.

Regards!

8 0
3 years ago
During the latest ice age on Earth, huge, frozen glaciers of snow and ice slowly crept along the surface of the planet. These gl
bixtya [17]
Cryosphere; geosphere
7 0
3 years ago
Read 2 more answers
Consider the reaction: CO2(g) + CCl4(g) ⇌ 2 COCl2(g) ΔG° = 46.9 kJ Under the following conditions at 25 oC: LaTeX: P_{CO_2}P C O
Mamont248 [21]

Answer : The value of \Delta G_{rxn} is, -47.0kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln K_p   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy  = 46.9 kJ

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

K_p = equilibrium constant

First we have to calculate the value of K_p.

The given balanced chemical reaction is,

CO_2(g)+CCl_4(g)\rightarrow 2COCl_2(g)

The expression for reaction quotient will be :

K_p=\frac{(p_{COCl_2})^2}{(p_{CO_2})\times (p_{CCl_4})}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

K_p=\frac{(0.653)^2}{(0.459)\times (0.984)}

K_p=0.944

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln K_p

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-46.9kJ/mol+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (0.944)

\Delta G_{rxn}=-47.0kJ/mol

Therefore, the value of \Delta G_{rxn} is, -47.0kJ/mole

3 0
3 years ago
When 2 moles of Na(s) react with H2O(l) to form NaOH(aq) and H2(g) according to the following equation, 369 kJ of energy are evo
enot [183]

Answer:

Exothermic

q = -8.03 kJ/g

Explanation:

<em>When 2 moles of Na(s) react with H₂O(l) to form NaOH(aq) and H₂(g) according to the following equation, 369 kJ of energy are evolved.</em>

The thermochemical equation is:

2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g)    ΔH = -369 kJ

Since the energy is evolved, the reaction is exothermic, which is why the enthalpy of the reaction (ΔH) is negative.

The heat released (q) per gram of Na(s) is (molar mass 22.98 g/mol):

\frac{-369kJ}{2molNa} .\frac{1molNa}{22.98gNa} =-8.03kJ/g

4 0
3 years ago
What dissolved species are present in a solution of naclo4? express your answers as ion separated by a comma?
Afina-wow [57]

The dissolved species that are  present  in solution of NaClO4 are Na+ ,   ClO4-

<h3>Explanation</h3>

when substance dissolve in water it dissociate  in ions. Some substance dissociate partially   when  they dissolve in water while others dissociate completely. NaClO4  is  a salt which dissociate completely   when it dissolve in water to give Na+ and CIO4-  ions

<h3 />
4 0
3 years ago
Read 2 more answers
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