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3 years ago

How can a solution become saturated?

Chemistry

2 answers:

vladimir2022 [97]3 years ago

7 0

Answer:

it think it is more solute added

Liono4ka [1.6K]3 years ago

3 0

Explanation:

Answer :more solute is added

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I'll give 40 pts for this one but pls help me....

Ivenika [448]

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3 years ago

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of nitrous acid and sodium hydroxide are

Bess [88]

Answer:

H+(aq) + OH-(aq) → H2O(l)

Explanation:

Step 1: Data given

nitrious acid = HNO3

sodium hydroxide = NaOH

Step 2: The unbalance equation

HNO3(aq) + NaOH(aq) →NaNO3(aq) + H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side (Ba^2+ and Br-), look like this:

H+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) →Na+(aq) +NO3(aq) + H2O(l)

H+(aq) + OH-(aq) → H2O(l)

7 0

4 years ago

I need help!! i need to make it like 3:2

anyanavicka [17]

Answer:

use visual studio code and put in this print{3:2}-1

Explanation:

4 0

3 years ago

A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

In-s [12.5K]

Answer:

3.6667

Explanation:

For helium gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.6}\times {3.0}={P_2}\times {9.0} atm$

${P_2}=\frac {{5.6}\times {3.0}}{9.0} atm$

${P_1}=1.8667\ atm$

The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm

For Neon gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${3.6}\times {4.5}={P_2}\times {9.0} atm$

${P_2}=\frac {{3.6}\times {4.5}}{9.0} atm$

${P_1}=1.8\ atm$

The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm

Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.

6 0

3 years ago

A solution was prepared by mixing 50.00 ml of 0.100 M of HNO3 and 100.00 ml of 0.200 M HNO3. Calculate the molarity of the final

valentina_108 [34]

Answer:

The molarity of this final solution is 0.167 M

Explanation:

Step 1: Data given

Volume of a 0.100 M HNO3 solution = 50.0 mL

Volume of a 0.200 M HNO3 = 100.0 mL

Step 2: Calculate moles

The final molarity must lie between 0.1M and 0.2M

Moles = molarity * volume

Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol

Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol

total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L

Step 3: Calculate molarity of final solution

Molarity = mol / volume

Molarity 0.025 moles /0.150 L

Molarity = 0.167M

The molarity of this final solution is 0.167 M

4 0

3 years ago