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romanna [79]
3 years ago
6

What does a measure of Xll on the Modified Mercalli scale indicate?

Chemistry
1 answer:
Alborosie3 years ago
6 0

Answer:2370934oiuaroiufaopruaeportourieiiiiriruoituweproitupwoierutpoiweurtpoiwuerptoirpoueportupoeriutpoieurpoiueroptiuwepotupeoritutpoieru

Explanation:eroptiueorupoeurtuertpoueorptupoerupoerutpoiweurtpoiuertopiuertopiueropituepoirutpoewrutopeurtouertpouerpotuwpeorutoutpourtpoiwuretpouwroptuepotuoeutpowiutpoieurtpoerutpowiutowuerpotiuepotuee

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Why is it easy to float on salt water instead of fresh water?
Elan Coil [88]
Answer:  
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Because salt water is denser than freshwater.
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5 0
3 years ago
Which of the following is true about homogeous mixtures
sergey [27]
Was there supposed to be a picture?
4 0
3 years ago
5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
Korolek [52]

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

<h3>What is a limiting reactant?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid CH_3CO_2H  reacts with baking soda NaHCO_3 according to the equation:

CH_3CO_2H  + NaHCO_3 → CH_3CO_2Na + CO_2 + H_2O

1. Molar mass of NaHCO_3 is 23+1+12+16×3 = 84 g/mol

= \frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}

= \frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}

=0.29 mol NaHCO_3

2. From the balanced equation we see that 1 mole of NaHCO_3 reacts with 1 mole of CH_3CO_2H , then 0.29 moles of NaHCO_3 react with 0.29 moles of CH_3CO_2H.

3. Mass of 1 mole of CH_3CO_2H is 12+ 1×3+12+16×2=60 g/mol

= \frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}

=17.4 g CH_3CO_2H

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g CH_3CO_2H is very close to 17.4 g CH_3CO_2H. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

Learn more about the limiting reactant here:

brainly.com/question/19654705

#SPJ1

4 0
2 years ago
Given its formula and Avogadro's Number (6.02 x 10^23 molecules/mol), deduce how many molecules are present in 3 x 10^-16 grams
marissa [1.9K]

Answer:

5 × 10⁵ molecules (500,000 molecules)

Explanation:

Step 1: Convert 3 × 10⁻¹⁶ g to moles

We will use the molar mass of TCDD (321.97 g/mol).

3 × 10⁻¹⁶ g × 1 mol/321.97 g = 9 × 10⁻¹⁹ mol

Step 2: Convert 9 × 10⁻¹⁹ mol to molecules

The required conversion factor is Avogadro's number (6.02 × 10²³ molecules/mol).

9 × 10⁻¹⁹ mol × 6.02 × 10²³ molecules/1 mol = 5 × 10⁵ molecules

3 0
3 years ago
Chemical reaction that releases energy, usually as heat
PolarNik [594]
Sodium has a very violent reaction with water. And burns in cold water having a highly exothermic reaction.
2Na + 2H2O ➡ 2NaOH + H2
7 0
4 years ago
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