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romanna [79]
3 years ago
6

What does a measure of Xll on the Modified Mercalli scale indicate?

Chemistry
1 answer:
Alborosie3 years ago
6 0

Answer:2370934oiuaroiufaopruaeportourieiiiiriruoituweproitupwoierutpoiweurtpoiwuerptoirpoueportupoeriutpoieurpoiueroptiuwepotupeoritutpoieru

Explanation:eroptiueorupoeurtuertpoueorptupoerupoerutpoiweurtpoiuertopiuertopiueropituepoirutpoewrutopeurtouertpouerpotuwpeorutoutpourtpoiwuretpouwroptuepotuoeutpowiutpoieurtpoerutpowiutowuerpotiuepotuee

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Please answer this, <br>Determine the weight of CaO produced by heating 70 g of CaCO3
mojhsa [17]
So first you work out the ratio. The formula tells us that for every one 'amount' of Ca and Cthere will be 3x the amount of oxygen. So, the ratio is 1:1:3, (=5) therefore 70g divided by 5 = 14.

If 70g of CaCO3 is heated there will be (1x14) 14g Ca, (1x14) 14g C and (3x14) 42g of O.

Weight of CaO= 42+14, 56g

(I hope this is right! Good luck xx)
6 0
4 years ago
Combustion analysis of an unknown compound provides the following data: 73.5 grams C, 4.20 grams H, and 72.3 grams Cl. What is t
tino4ka555 [31]
The  %  composition  of  each  element  is  calculated  as   follows

=  mass   of  the  element/total  mass   x100

total  mass=  73.5+4.2+72.3=150
%  composition  of  C  =  73.5/150 x100=49%

%  composition  of  H= 4.2/150 x100=  2.8%

%composition  of  Cl=  72.3/150  x100=  48.2%
8 0
4 years ago
ANSWER QUICK PLEASE ILL GIVE BRAINLIEST AND 50 POINTS
yawa3891 [41]

Answer:

Single replacement and Zinc Sulfate

the 2nd one is double replacement and potassium nitrate

5 0
2 years ago
Read 2 more answers
An unknown atom has 5
labwork [276]

Answer:

17

Explanation:

the atomic mass is away protons + neutrons, electrons are neglatable.

7 0
3 years ago
All organisms use oxidation-reduction reactions to harness energy, and this newly harvested energy is used to produce atp. oxida
Ber [7]
1. In first reaction reactant a is the electron donor, while b is the electron acceptor,
the oxidized product is c while the reduced product is d

2. in the second equation e is the electron donor, f is the electron acceptor
g is the oxidized product while h is the reduced product.

3. In the third reaction i is the electron donor, j is the electron acceptor , k is the oxidized product while l is the reduced product.
4 0
4 years ago
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