<span>A
hair stylists works ¼ to trim customer’s hair
=> 1/6 to style customer’s hair
=> 1/6 + ¼
Find the least common multiple of both denominator:
=> 1/6 + ¼ = 10/24
Simplify
=> 5/12
Now, he works 3 1/3 hour each day in 5
days
=> 3 1/3 x 5
=> 16 ½ hours in 5 days
Now, divide
=> 16 ½ divided by 5/12
=> 39 ; approximately 39 customer in 5 days can a hairstylist accommodate.</span>
Let ax+by=c be the given(known) line
slope of this line (m₁) = -a/b
Let m₂ be the slope of required line
Since given line and required line are perpendicular to each other, the product of their slopes must be equal to -1
Therefore, m₁.m₂ = -1
(-a/b)m₂ = -1
m₂ = b/a
Therefore, by slope-intercept form, line perpendicular to given line can be given by,
y=m₂x+c
y=(b/a)x+c
Therefore, ay-bx=c
or bx-ay+c = 0
Where c is constant and it can be determined according to the conditions given in questions.
Therefore the required line is,
bx-ay+c=0
To answer this item, I would assume that the pasture is in a rectangular form. The area of a rectangle is the product of the dimensions. Let x be one of the sides of the pasture and the other dimension will become x+2. The equation that would best represent the scenario is,
<em>A = (x)(x + 2)</em>
