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1 year ago

If anyone can help me to solve this.

Mathematics

2 answers:

Travka [436]1 year ago

8 0

$\large\underline{ \cal{SOLUTION:}}$

$\large \bold{x + 1 = 9}$

$\large \bold{x = 9 - 1}$

$\large \bold{x = \red{8}}$

$\:$

$\large\underline{ \cal{CHECKING:}}$

Put x = 8

$\large{ \bold{ \underline{ \red{8} }+ 1 = 9}}$

$\large \bold{-N} \frak{unx-}$

Mademuasel [1]1 year ago

3 0

Explanation:

Equation: x + 1 = 9

Solving Steps:

x + 1 = 9 (<em>subtract both sides by 1)</em>

x + 1 - 1 = 9 - 1 (<em>simplify the following)</em>

x = 8

Then check for solution:

x + 1 = 9

[insert x = 8]

8 + 1 = 9

9 = 9

As both sides are equal, the statement is true.

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1 year ago

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$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

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$c_1 + c_2 = 1$

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By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

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By plugging the values of $y_1$ and

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Read 2 more answers

If anyone can help me to solve this.​

If anyone can help me to solve this.