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3 years ago

Is a diamond a homogeneous or heterogeneous mixture or a substance

Chemistry

1 answer:

DerKrebs [107]3 years ago

5 0

Answer:

heterogeneous

Explanation:

It's a heterogeneous mixture. Diamond is made of just one element: carbon. Each carbon atom in diamond is connected to four other carbon atoms, in a crystal that extends on and on. There are other forms of pure carbon where the atoms are bonded differently, notably charcoal and graphite.

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What are twoparts of an atom

Leto [7]

The answer is neutrons and protons.

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3 years ago

Farmer brown is planting crops in his feild s. He wants to prevent the topsoil from being blown away by the wind or washed away

Ratling [72]

Hey!

I would say the answer is A. Plow the soil many times to lessen the chance of the topsoil being blown away.

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3 years ago

Read 2 more answers

What is a precipitation <br>reaction?

ivolga24 [154]

Answer:

A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.

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3 years ago

Coal can be converted to methane gas by a process called coal gasification. The equation for the reaction is the following: 2 C

zloy xaker [14]

Answer:

24 g of C are needed to produce 1mol of CH₄

Explanation:

The reaction is:

2C (s) + 2H2O (l) → CH4(g) + CO2 (g)

2 moles of carbon react with 2 moles of water in order to produce 1 mol of methane and 1 mol of carbon dioxide.

If we want to produce 1 mol of methane, we need 2 moles of C

Let's find out the mass → 2 mol . 12 g/1 mol = 24g

3 0

3 years ago

Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For ro

Nata [24]

Answer:

$\boxed{\text{199 mL}}$

Explanation:

1. Calculate the moles of HCl

$n = \text{25.4 g} \times \dfrac{\text{1 mol}}{\text{36.46 g}} = \text{0.6967 mol}$

2. Calculate the volume of dilute HCl

$\begin{array}{rcl}\text{Molar concentration}& =& \dfrac{\text{moles}}{\text{litres}}\\\\3.50 & = & \dfrac{0.6967}{V}\\\\3.50V & = & 0.6967\\\\V & = & \dfrac{0.6967}{3.50}\\\\V & = & \text{0.199 L} =\textbf{199 mL}\end{array}\\\text{The volume of muriatic acid needed is }\boxed{\textbf{199 mL}}$

3 0

3 years ago