Answer:
b, c,d
Explanation:
b. There are gas molecules that move faster than the average.
c. All the gas molecules in a sample cannot have the same kinetic energy.
d. The average kinetic energy of gas molecules increase with increasing temperature.
Answer : The acid dissociation constant Ka of the acid is, 
Explanation :
First we have to calculate the concentration of hydrogen ion.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
Given: pH = 4.06
![4.06=-\log [H^+]](https://tex.z-dn.net/?f=4.06%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=8.71\times 10^{-5}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D8.71%5Ctimes%2010%5E%7B-5%7DM)
The dissociation of acid reaction is:

Initial conc. c 0 0
At eqm. c-cα cα cα
Given:
Degree of dissociation = α = 0.10 % = 0.001
![[H^+]=c\alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Calpha)


The expression of dissociation constant of acid is:
![K_a=\frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)

Now put all the given values in this expression, we get:


Thus, the acid dissociation constant Ka of the acid is, 
Answer: 
Explanation:
Given
Mass of iron piece is 
Heat absorbed 
Temperature changes from
i.e.

Heat absorbed is given by ![Q=mc\Delta T\quad [c=\text{specific heat of material}]](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5Cquad%20%5Bc%3D%5Ctext%7Bspecific%20heat%20of%20material%7D%5D)
Insert the values

Thus, the specific heat of iron is 
Atom is the
most basic unit of matter. They are the general term used to describe pieces of
matter. But a different kind of atom makes up an element. A combination of atom of different elements
creates a molecule. For example, you have water; it has a chemical formula of
H2O. If you separate H from O, you have two atoms. Two atoms for hydrogen and
one atom for oxygen. However, they are of different elements. And when you
combine them to form H2O, you create a molecule.
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Answer:
a) The work done is 10.0777 kJ
b) The water's change in internal energy is -122.1973 kJ
Explanation:
Given data:
1 mol of liquid water
T₁ = temperature = 100.9°C
P = pressure = 1 atm
Endothermic reaction
T₂ = temperature = 100°C
1 mol of water vapor
VL = volume of liquid water = 18.8 mL = 0.0188 L
VG = volume of water vapor = 30.62 L
3.25 moles of liquid water vaporizes
Q = heat added to the system = -40.7 kJ
Questions: a) Calculate the work done on or by the system, W = ?
b) Calculate the water's change in internal energy, ΔU = ?
Heat for 3.25 moles:

The work done:

The change in internal energy:
