Balanced Half reactions are:
At anode 2
==> Cl₂+ 
+ H₂O ==> 
+ 2
+
At Cathode: 2 + ==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, , 
and
Now at Anode reaction will occur as given:
2 ==> Cl₂+ + H₂O ==> + 2 + (will occur)
At Cathode:
2 + ==> H₂ (will occur)
At Cathode:
+ ==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution, will be reduced before .
The reduction potentials for is zero whereas reduction potential for is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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<span>
As a liquid is heated, its vapor pressure increases until the vapor pressure
equals the pressure of the gas above it.
Bubbles of vaporized liquid (i.e., gas) form within the bulk liquid and
then rise to the surface where they burst and release the gas. (At
the boiling temperature the vapor inside a bubble has enough pressure to
keep the bubble from collapsing.)
In order to form vapor, the molecules of the liquid must overcome the forces
of attraction between them.<span>
The temperature of a boiling liquid remains constant, even when more heat
is add.</span></span>
Answer:
The projection of the Fisher projection of D-Fructose and D-glucose is that The carbonyl carbon in D-glucose is carbon 1 (aldehyde), whereas in D-fructose, the carbonyl group is on carbon 2 (ketone).
Explanation:
An aldehyde is a compound containing a functional group with the structure −CHO, consisting of a carbonyl center and
A ketone is a functional group with the structure RC(=O)R', where R and R' can be a variety of carbon-containing substituents.
<span><span><span>
D- coal-burning stove </span>is the correct answer</span></span>
