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Hatshy [7]
2 years ago
8

How do I convert these probs? into base 10 4120_7, A3B_12, WXYZ_36

Mathematics
1 answer:
natali 33 [55]2 years ago
7 0

4120_7 = 4•7³ + 1•7² + 2•7¹ + 0•7⁰

4120_7 = 4•343 + 1•49 + 2•7 + 0•1

4120_7 = 1372 + 49 + 14

4120_7 = 1435

In base 12, we use the digits 0-9 as well as A for 10 and B for 11. So

A3B_12 = 10•12² + 3•12¹ + 11•12⁰

A3B_12 = 10•144 + 3•12 + 11•1

A3B_12 = 1440 + 36 + 11

A3B_12 = 1487

In base 36, we assign values between 10 and 35 to the letters A-Z, so that

WXYZ_36 = 32•36³ + 33•36² + 34•36¹ + 35•36⁰

WXYZ_36 = 32•46656 + 33•1296 + 34•36 + 35•1

WXYZ_36 = 1492992 + 42768 + 1224 + 35

WXYZ_36 = 1537019

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