Answer:
39
Step-by-step explanation:
Let the three consecutive odd numbers be:
x+2, x+4, x+6.
The sum of the consecutive numbers is 123 i.e
x+2 + (x+4) + (x+6) = 123
x + 2 + x + 4 + x + 6 = 123
3x + 12 = 123
Collect like terms
3x = 123 — 12
3x = 111
Divide both side by the coefficient of x i.e 3
x = 111/3
x = 37
Now let us find the value of the three odd numbers. This is illustrated:
1st : x + 2 = 37 + 2 = 39
2nd : x + 4 = 37 + 4 = 41
3rd : x + 6 = 37 + 6 = 43
The smallest of the three consecutive odd numbers is 39
We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Answer:
6v^3
Step-by-step explanation:
i think so. dont critisize me
Answer:
Step-by-step explanation:
Given
and 
Required
Which compares them correctly
This is incorrect because 0.63 is greater
This is also incorrect because 0.63 is greater
This is also correct because 0.63 is greater
This is also incorrect because 0.63 is greater
