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3 years ago

What is the value of x? (6x + 10) (x + 17) (4x - 34)

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

Step-by-step explanation:

180=x+17+6x+10+4x-34

180=11x-7

11x=187

x=17

patriot [66]3 years ago

5 0

Answer:

6x + 10 + x + 17 + 4x - 34 = 180

11x - 7 = 180

11x = 180 + 7

x = 187 ÷ 11

x = 17

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zimovet [89]

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8 0

3 years ago

(8–9a)a=−40+(6–3a)(6+3a)

elena-14-01-66 [18.8K]

Answer:

a=-0.5

Step-by-step explanation:

Distributive property for left side, difference of squares for right side.

8a-9a^2=-40+36-9a^2

-9a^2 cancels out

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8 0

4 years ago

Read 2 more answers

Evaluate the limit of

tekilochka [14]

Answer:

Option a is correct -- $\frac{9}{2}$

Step-by-step explanation:

If we put infinity directly into the expression we get ∞ + ∞ expression. In order to circumvent it we divide both numerator and denominator with the greatest exponent.

$\lim_{x \to \infty} \frac{9n^{3}+5n-2}{2n^{3}}$

Divide each term by n³

$=\lim_{x \to \infty} \frac{\frac{9n^{3}}{n^{3}}+\frac{5n}{n^{3}} -\frac{2}{n^{3}}}{\frac{2n^{3}}{n^{3}} }$

$=\lim_{x \to \infty}\frac{9(1)+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2(1)} } \\=\lim_{x \to \infty}\frac{9+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2}} \\\\by putting n = infinity \frac{5}{n^{2}} becomes 0 and\frac{2}{n^{3}} becomes 0 \\=\frac{9+0-0}{2} \\=\frac{9}{2}$