A footbridge is in the shape of an arc of a circle. The bridge is 7 ft tall and 29 ft wide. What is the radius of the circle tha
t contains the bridge? Round your answer to the nearest tenth.
1 answer:
Answer:
18.5 ft (to the nearest tenth)
Step-by-step explanation:
The diameter of the circle passes through the center of the circle and divides the width of the circle into two equal parts.
We complete the circle and apply the <u>Law of Intersecting Chords.</u>
In the diagram, by this law:
AB X BC =DB X BE
7*x=14.5X14.5
x=14.5X14.5÷7
x=30.04
Therefore:
Length of the Diameter= 7+30.04 ft=37.04 ft
Radius =37.04/2= 18.5 ft
You might be interested in
Answer:
x = lillies
y = tulips
x + y = 13
1.25x + .90y = 14.85
-1.25x - 1.25y = -16.25
1.25x + .90y = 14.85
-0.35y = -1.40
y = 4 tulips
x + 4 = 13
x = 9 lillies
(9 lillies, 4 tulips)
Step-by-step explanation:
Pretty sure its 3 chapters an hour
Becouse if she reads 3 chapters per hours it will be 3 X 6=18
Ex: 3 4/5 = 3 x 5 + 4= 19/5
The answer to the first one is C
Second part is x^2 - 12 (B)