Question

A footbridge is in the shape of an arc of a circle. The bridge is 7 ft tall and 29 ft wide. What is the radius of the circle that contains the bridge? Round your answer to the nearest tenth.

Answer 1

Answer:

18.5 ft (to the nearest tenth)

Step-by-step explanation:

The diameter of the circle passes through the center of the circle and divides the width of the circle into two equal parts.

We complete the circle and apply the Law of Intersecting Chords.

In the diagram, by this law:

AB X BC =DB X BE

7*x=14.5X14.5

x=14.5X14.5÷7

x=30.04

Therefore:

Length of the Diameter= 7+30.04 ft=37.04 ft

Radius =37.04/2= 18.5 ft