A footbridge is in the shape of an arc of a circle. The bridge is 7 ft tall and 29 ft wide. What is the radius of the circle tha
t contains the bridge? Round your answer to the nearest tenth.
1 answer:
Answer:
18.5 ft (to the nearest tenth)
Step-by-step explanation:
The diameter of the circle passes through the center of the circle and divides the width of the circle into two equal parts.
We complete the circle and apply the <u>Law of Intersecting Chords.</u>
In the diagram, by this law:
AB X BC =DB X BE
7*x=14.5X14.5
x=14.5X14.5÷7
x=30.04
Therefore:
Length of the Diameter= 7+30.04 ft=37.04 ft
Radius =37.04/2= 18.5 ft
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