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steposvetlana [31]
3 years ago
13

A footbridge is in the shape of an arc of a circle. The bridge is 7 ft tall and 29 ft wide. What is the radius of the circle tha

t contains the bridge? Round your answer to the nearest tenth.

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

18.5 ft (to the nearest tenth)

Step-by-step explanation:

The diameter of the circle passes through the center of the circle and divides the width of the circle into two equal parts.

We complete the circle and apply the <u>Law of Intersecting Chords.</u>

In the diagram, by this law:

AB X BC =DB X BE

7*x=14.5X14.5

x=14.5X14.5÷7

x=30.04

Therefore:

Length of the Diameter= 7+30.04 ft=37.04 ft

Radius =37.04/2= 18.5 ft

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Answer:

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Step-by-step explanation:

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3 years ago
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Zigmanuir [339]
  48
+14
-------
  62

If you need more work:

Ones place: 8+4=12
Tens place: 40+10=50
Add up: 50+12=62
3 0
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Answer:

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Step-by-step explanation:

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