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pychu [463]
3 years ago
9

Find the area of the trapezoid

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

20 is the answer

Step-by-step explanation:

I did the math.hope it helps :)

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If f is a linear function, f(k)=16 and f(-k)= -4 then what is the value of f(0)?​
ira [324]

f(0) =  ( f(k) +f(-k) ) / 2

f(0) = (16 - 4) / 2

f(0) = 12 / 2

f(0) = 6  → ANSWER

*Remember that f(0) = m(0) + n = n

If we have f(x) = mx + n, then:

f(k)= mk + n     and       f(-k)= -mk + n

If we add them:

  f(k) + f(-k)

= mk + n -mk + n

= 2n

= 2f(0)

So we conclude that:

f(0) = [f(k) + f(-k)] / 2

3 0
3 years ago
An area of a hexagon of 15 feets sides<br>​
Vlada [557]

Answer:

225

Step-by-step explanation:

6 0
3 years ago
Graph the line with this equation y = x + 4​
zhannawk [14.2K]

Answer:

Step-by-step explanation:

5 0
3 years ago
See attached photo below
Daniel [21]

Answer:

  • Library 2 charges more for each book loaned.
  • Library 1 has a cheaper subscription fee.

Step-by-step explanation:

Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...

  y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values

  y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit

  y = 1.75x -3.50 +15.50 . . . . . . simplify more

In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...

  C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1

_____

Now, we can answer the questions.

Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)

Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)

_____

The numbers in the cost equations are ...

  C = (subscription fee) + (cost per book loaned)·n

8 0
3 years ago
6x squared plus 12x plus 13 equals 2x squared plus 4
Andrews [41]
12x^2+12x+3=2x^2+4\\\\12x^2-2x^2+12x+3-4=0\\\\10x^2+12x-1=0\\\\a=10;\ b=12;\ c=-1\\\\\Delta=12^2-4\cdot10\cdot(-1)=144+40=184\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{184}=\sqrt{4\cdot46}=2\sqrt{46}\\\\x_1=\frac{-12-2\sqrt{46}}{2\cdot10}=\frac{-6-\sqrt{46}}{10};\ x_2=\frac{-12+2\sqrt{46}}{2\cdot10}=\frac{-6+\sqrt{46}}{10}
6 0
3 years ago
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