Can someone help me please

Mathematics

1 answer:

zmey [24]3 years ago

4 0

Answer:

The financial aid covers $ 1,875

Student needs to pay out-of-pocket $635

Step-by-step explanation:

(2,500) * (3/4) = 7500/4 = 1,875

2,500 - 1,875 = 635

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5,4,16/5 find the 10th term

Aleks04 [339]

the sequence is 25/4(4/5)^x

plug in 10 for x to get your solution:

25/4(4/5)^10=4^9/5^8

7 0

3 years ago

√25x+75 +3√x-2 =2+4√x-3 +√9x-18

Otrada [13]

Answer:

Step-by-step explanation:

$\large \boldsymbol{ \boxed{\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b} }} \\\\\\ \sqrt{25x+75} +3\sqrt{x-2} =2+4\sqrt{x-3} +\sqrt{9x-18} \\\\ \sqrt{25} \cdot \sqrt{x+3}+3\sqrt{x-2} =2+4\sqrt{x-3} +\sqrt{9}\cdot \sqrt{x-2} \\\\5\sqrt{x+3} +3\sqrt{x-2} \!\!\!\!\!\!\!\!\!\!\bigg{/} \ \ =2 +4\sqrt{x-3} +3\sqrt{x-2} \!\!\!\!\!\!\!\!\!\!\bigg{/} \\\\(5\sqrt{x+3})^2 =(2+4\sqrt{x-3} )^2 \\\\ \ \ \ let \ \ t=x+3 \ \ ; \ \ \ t-6=x-3 \\\\ \big(5\sqrt{t} \ \big)^2=(2+\sqrt{t-6} )^2 \\\\$ $\large \boldsymbol{} 25t=4+16\sqrt{t-6} +16(t-6) \\\\(9t+92)^2=(16\sqrt{t-6} )^2 \\\\81t^2+1656t+8464=256(t-6)\\\\81t^2+1400t+10000=0 \\\\ D=1400^2-324000=-128000=> \\\\D$