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____ [38]
3 years ago
13

Equation of a line that goes through point (4,2) and perpendicular to -x+y=1

Mathematics
2 answers:
mojhsa [17]3 years ago
3 0

Answer:

hsgdcsjavebiav2gwjevd

aleksklad [387]3 years ago
3 0

Answer:

y= -x + 6

Step-by-step explanation:

-x + y =1 ---> y = x+1

the line perpendicular to this line should have negative inverse slope

the slope is 1 so the negative inverse of 1 is -1

set up

y = -x +b

since it goes through (4,2)

then we have

2 = -4 +b

b=6

so the linear equation is y = -x+6

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LiRa [457]
Hope this helps you out 3w+7=8

The answer is w= 1/3

Step by step:

3w+7=8
Step 1: is subtract is 7 from both sides.
3w+7-7=8-7
3w=1

Step 2: Divide both sides by 3.
3w/3 = 1/3

Your solution is:

w=1/3
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