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earnstyle [38]
3 years ago
10

A lighthouse keeper has a 10º angle of depression between the horizontal light beam and the line of sight from the ship. If the

keeper is 19 m above water, how far is the ship from the base of the lighthouse?

Mathematics
2 answers:
Mademuasel [1]3 years ago
7 0
The image I provided is a good diagram of the situation.

The keeper is 19 meters above the water.

He is looking down at a ship at a 10° angle from the horizon.

We want to find the distance between the base of the lighthouse and the ship.

The side we are trying to find is opposite the angle 10°. The lighthouse is adjacent to the angle 10°.

Therefore, we can use the tangent function (opposite over adjacent).

tan 10° = x/19

Multiply both sides by 19:

19 tan 10° = x

Solve using a calculator:

x = 3.350 meters

The ship is 3.350 meters from the lighthouse.

DerKrebs [107]3 years ago
6 0
3.350 is the answer i hope this help
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Answer:

x = 12    y = 24     z = 12\sqrt{3}

Step-by-step explanation:

you are correct.  x = 12

The dotted line has a length of 12 also

The dotted line is the shorter leg of the 30-60-90 triangle.

So, z = 12\sqrt{3} and y = 24

8 0
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What is <br>453%÷487.2493×497​
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3 years ago
Using a Graph to Understand a Linear Function
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The tree was 40 in tall when planted

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3 years ago
The perimeter of a rectangle is 48 m. The width of the rectangle is 2 more than half the length. Find the length and the width
Ksivusya [100]

Answer:

Length = 14.6667

Width = 9.33333

Step-by-step explanation:

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3 0
4 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
4 years ago
Read 2 more answers
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