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3 years ago

Can 14, 18, and 31 form a triangle ?

Mathematics

1 answer:

guapka [62]3 years ago

5 0

Answer: Yes, they can.

Clarification:

We have three different sides with different lengths:

$\mathrn {14, 18, 31}$

These three lengths can form a triangle, an isosceles triangle.

Isosceles triangles have three different side lengths.

Hope this helps you. Best of Luck!

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Aljan and Bella are both driving from Cleveland to Chicago. Aljan leaves at

Natalija [7]

Answer:

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

Step-by-step explanation:

In order to calculate the number of hours, "x", that it'll take for Bella to pass Aljan, we need to find the value of "x" that makes both equations equal. Therefore,

$60*x + 20 = 65*x\\65*x - 60*x = 20\\5*x = 20\\x = \frac{20}{5} = 4$

In order to calculate the distance they traveled, we must use this value for "x" in any of the equations, as done below:

$y = 65*4\\y = 260$

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

4 0

3 years ago

#10 - Alvin ate 1/3 of a pizza for dinner and took 1/6 of eight for lunch the next day. How much of the pizza does he have left?

Delvig [45]

He has 1/2 of the pizza left.

8 0

3 years ago

Find the missing terms.<br> 3, _____, _____, 21 (arithmetic)

Rom4ik [11]

Answer:

Hello There!!

Step-by-step explanation:

The answer is 3,9,15,21.

hope this helps,have a great day!!

~Pinky~

4 0

3 years ago

Read 2 more answers

I suck at math can someone help please??

Zielflug [23.3K]

6/7 × 4 would be the correct answer. This is because 6/7 × 4= 3 3/7 which is equal to 4/7 × 6= 3 3/7. No other expression would equal 4/7 × 6

7 0

3 years ago

Write an exponential equation in the form y = ab* whose graph passes through points (2, 18) and (5, 60.75).

DochEvi [55]

Let $y=ab^x,$ as described in the problem statement. Plugging in $x=2$ and $x=5$ gives us the equations $18=ab^2$ and $60.75=ab^5.$ Since $a,b$ are nonzero, we divide the second equation by the first to get $\frac{27}{8}=b^3,$ which means that $b=\frac{3}{2},$ after taking the cube root. Plugging this value for $b$ into the first equation, we now have $18=a(3/2)^2=\frac{9a}{4}.$ Solving gives $a=8,$ and our desired exponential equation is $\boxed{y=8\left(\frac{3}{2}\right)^x}.$

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3 years ago